Each value of n is a different eighth-note. There are four measures, so compute the values of base(n), tenor(n) and alto(n) for the first 32 values of n (0 through 31). These four measures repeat forever. It is a really annoying melody that will be stuck in your head for twelve days.
You can write a program to produce the right values, or you can do it by hand. Below are recursively defined math functions (not C code).
First, the base and tenor part numbers represent half steps, where 0 is middle C. Therefore, -3 is A and 5 is F. 3 is E flat.
foundation(0) = 0
foundation(n) = 5 + foundation(n-1)
m(n) = foundation(RoundDownToInteger(n/8))
base(n) = (( m(n) + 6 ) % 12) - 6
c(0) = 0
c(n) = 2 + c(n - 1)
t(n) = c(n) % 6
tenor(n) = if RoundDownToInteger(n/8) is even, t(n % 8) + base(n)
else base(n)
Second, the alto part numbers are not half steps, but rather are positions
along a major scale, relative to the value of the base(n) note.
This is a major scale starting at the basenote and going up -- the base
note is the tonic of the scale, like the key you are in changes according
to the base note. By the way, the base note is either 0 or 1 -- I think
it is 1 but I forget -- try it both ways to see which sounds better.
q(0,i,j,x) = x
q(n,i,j,x) = if (j==0), q(n-1, i+1, i+1, (-1)x)
else q(n-1,i,j-1,x)
arrow(n) = q(n,0,0,-1)
a(0) = 2
a(n) = a(n - 1) + arrow(n - 1)
alto(n) = if RoundDownToInteger(n/8) is odd, a(n % 8)
else 5
Show your work. You get one point for producing the sequence of notes, or you can get two points for performing (voice, whistle, or playing a tape of) the correct tune in class on the day it is due.
Good luck, may the Force be with you, and don't forget to wear ear plugs.